How to graph a parabola $y = \frac{1}{4} x^{2}$ $y=1/4x^2$ ?

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Answer 1 · 2015-05-12T09:42:54

Well,if you are concerned with this question, firstly you can write it as $4 y = x^{2}$ $4y= x^2$ ,

Now as i said earlier the curve will be bent towards that axis which has less power irrespective of the coefficient of x and y .

About this question, you can see that y has less power so the curve will be bent towards y axis.the graph will be as follows,

graph{x^2/4 [-10, 10, -5, 5]}

Here's another method you could use.

You can put different values of x keeping y constant and note the points that you will get; similarly, you can find values of y keeping x constant.

You can plot these points on the graph and the same graph would be in front of you.

Answer 2 · 2016-06-23T10:34:56

Choose x-values, work out the y-values and plot points.
Join them with a smooth curve to obtain the graph.

The first thing is to have some points to plot to be able to find out what the graph will look like.

Draw a table and select some suitable x values.
$x : - 4, - 3, - 2, - 1, - 1, 2, 3, 4$ $x: -4, -3, -2, -1, - 1," " 2," " 3," " 4$

For each x-value, substitute into the equation given and calculate the y-values,

$y : 4, 2.25, 1, 0.25, 0, 0.25, 1, 2.25, 4$ $y: 4," "2.25," " 1," " 0.25," " 0," " 0.25, " " 1, " " 2.25," " 4$

Notice that the $y$ $y$ -values are all positive and are symmetrical on either side of $0$ $0$

Now plotting the points on a set of axes will give the graph of the parabola.
graph{y=1/4x^2 [-9.42, 10.58, -1.64, 8.36]}

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