How do you factor #15abc^2 + 6a^2bc - 6ab + 3bc#?
1 Answer
May 14, 2015
Answer:
-
See it as
#x-y#
#x=15abc^2+6a^2bc#
#y=(6ab+3bc)#
So,#(15abc^2+6a^2bc) - (6ab+3bc)# -
Factorise the common factor,
#(15abc^2+6a^2bc)= 3abc(5c+2a)#
#(6ab+3bc)= 3b(2a+3c)#
