How do you solve #abs(4d + 7) = 5#?

1 Answer
Miles A.
May 16, 2015

To solve for #d# we look at both ends of the absolute where it will equal either #5# or #-5# so this is what we do.

#abs(4d + 7) = 5#

can be re written as

#4d + 7 = 5# or #4d + 7 = -5#

#4d = -2# or #4d = -12#

#d = -1/2# or #d = -3#

keep in mind that the absolute sign means that what ever is inside the "Brackets" of the absolute, will always be positive, thus if the result inside is #abs(-5)# it will equal #5# ...

to rewrite #abs(-5) = 5#

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