How do you solve $- 3 < x - 3 < 0$ $-3<x-3<0$ ?

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Answer 1 · 2015-05-17T08:44:53

to solve for $- 3 < x - 3 < 0$ $-3< x - 3 < 0$

we would just need to add $3$ $3$ to each element in the equation.

$- 3 + 3 < x - 3 + 3 < 0 + 3$ $-3 + 3 < x - 3 + 3 < 0 + 3$

which will leave us with our answer.

$0 < x < 3$ $0< x < 3$

How do you solve −3<x−3<0-3<x-3<0?