How do you find the limit of $sin (x + 4 sin x)$ $sin(x+4sinx)$ as x approaches pi?

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Answer 1 · 2015-05-18T21:01:21

$lim_(x->pi) sin(x + 4sinx) = sin(pi + 4sinpi)$

we know that $color(red)(sinpi = 0)$
thus we have:

$= sin(pi + 4(0))$
$= sinpi$
$=0$

How do you find the limit of sin(x+4sinx)sin(x+4sinx)sin(x+4sinx) as x approaches pi?