What is the limit of sin[(pix) /(2-3x)]sin[πx23x] as x approaches infinity?

1 Answer
May 19, 2015

to solve for lim_(x->oo) sin((pix)/(2-3x))

we simplify by dividing the inner function by x

lim_(x->oo) sin(pi/((2/x)-3))

we know that color(red)( lim_(x->oo) 2/x= 0 )

thus we get:

= sin(pi/(0-3)) = sin(-(pi/3))

= - sin(pi/3)

=- (sqrt(3)/2)