Question

Question #a8f53

Answer 1

To make sure I have your data right:

There are 35 students, 21 are female, thus 14 male.

to solve for a)

we fist solve for what the probability of getting a female main rep.
which is the first student selected.

thus we take `1` student from the class of `35` and the probability that the student is female is:

`P`female main rep`= 21/35`

now one student is taken, and we left with `34` to select the alternative, which would looking at the chances its a male:

`P`male alternative `= 14/34`

we know here that `P(A nn B) = P(A).P(B)`

thus the answer to a) would be:

`(21/35)(14/34) = 0.247` or `24.7%`

now for b)

we will use the same reasoning, thus the first selected will be `1` male:

`P`male main rep`=(14/35)`

and then we are selecting another male, which there is now `1` less as we chose `1` as the main rep, and can not be chosen again, so we have:

`P`male alternative `=(13/34)`

which will lead us to our answer to b) as:

`(14/35)(13/34) = 0.153` or `15.3%`