How do you evaluate ${(- \frac{27}{8})}^{\frac{4}{3}}$ $(-27/8)^(4/3)$ ?

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Answer 1 · 2015-05-25T16:52:55

${(- \frac{27}{8})}^{\frac{4}{3}}$ $(-27/8)^(4/3)$

$= {({(- \frac{27}{8})}^{\frac{1}{3}})}^{4}$ $=( (-27/8)^(1/3))^4$

$= {(\frac{\sqrt[3]{- 27}}{\sqrt[3]{8}})}^{4}$ $= ((root(3)(-27))/root(3)(8))^4$

$= {(- \frac{3}{2})}^{4}$ $= (-3/2)^4$

$= \frac{81}{16}$ $= 81/16$

How do you evaluate (−278)43(-27/8)^(4/3)?