Question

How do you solve the system `−3x + y = 2` and `4x + 2y = 4`?

Answer 1

`-3x + y =3 => y = 3 +3x` ;
`4x + 2y = 4 => 4x + 2*(3+3x)= 4 => 4x+6+6x=4`
`=> 10x +6 =4 => 10x =-2 => x=-2/10=-1/5`
`y=3+3x => y=3+3*(-1/5) => y= 3-3/5 => y= 15/5 - 3/5`
`y= 12/5`