How do you determine if rolles theorem can be applied to #f(x)= 3sin(2x)# on the interval [0, 2pi] and if so how do you find all the values of c in the interval for which f'(c)=0?

1 Answer
May 29, 2015

The Rolles theorem says that if:

  1. #y=f(x)# is a continue function in a set #[a,b]#;
  2. #y=f(x)# is a derivable function in a set #(a,b)#;
  3. #f(a)=f(b)#;

then at least one #cin(a,b)# as if #f'(c)=0# exists.

So:

  1. #y=3sin(2x)# is a function that is continue in all #RR#, and so it is in #[0,2pi]#;
  2. #y'=6cos(2x)# is a function continue in all #RR#, so our function is derivable in all #RR#, so it is in #[0,2pi]#;
  3. #f(0)=f(2pi)=0#.

To find #c#, we have to solve:

#y'(c)=0rArr6cos(2c)=0rArrcos(2c)=0rArr#

#2c=pi/2+2kpirArrc=pi/4+kpirArr#

#c_1=pi/4#

and

#c_2=pi/4+pi=5/4pi#.

(both the values are #in[0,2pi]#).