How do you solve the system $y= 2x + 10$ and $y= 130$ by substitution?

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Answer 1 · 2015-05-30T03:11:12

$y = 2x+10$
and $y =130$

we substitute the given value of $y$ in the first equation:

$y = 2x+10$
$130 = 2x+10$
$120 = 2x$
$x=60$

hence the solutions are $color(green)(x=60 , y = 130$

How do you solve the system y= 2x + 10y= 2x + 10 and y= 130y= 130 by substitution?