How do you write #y+1/3 = 1/4(x-3)# in standard form?

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Answer 1 · 2015-05-31T10:08:46

#y+1/3=1/4(x-3)#

To get rid of the fractions, multiply both sides #12#:

#12(y+1/3)=12xx1/4(x-3)#

#12y+4=3(x-3)#

#12y+4=3x-9#

Standard form :
#Ax+By=C#

Rearrange to get:

#color(green)[3x-12y=13#