How do you FOIL $(2 y - 5) (y + 9)$ $(2y - 5)(y + 9)$ ?

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How do you FOIL $(2 y - 5) (y + 9)$ $(2y - 5)(y + 9)$ ?

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Answer 1 · 2015-05-31T11:18:14

= $2 y^{2} + 13 y - 45$ $2y^2+13y-45$

To foil $(2 y - 5) (y + 9)$ $(2y-5)(y+9)$ you first $2 y \times y$ $2yxxy$ and $2 y \times 9$ $2yxx9$ and $- 5 \times y$ $-5xxy$ and $- 5 \times 9$ $-5xx9$

giving $2 y^{2} + 18 y - 5 y - 45$ $2y^2 + 18y -5y -45$

simplified= $2 y^{2} + 13 y - 45$ $2y^2+13y-45$

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How do you FOIL $(2 y - 5) (y + 9)$ $(2y - 5)(y + 9)$ ?

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