How do you FOIL #(2y - 5)(y + 9)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Hayden L. May 31, 2015 =#2y^2+13y-45# To foil #(2y-5)(y+9)# you first #2yxxy# and #2yxx9# and #-5xxy# and #-5xx9# giving #2y^2 + 18y -5y -45# simplified=#2y^2+13y-45# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1847 views around the world You can reuse this answer Creative Commons License