How do you FOIL #(3y+ - 2)(2y+ - 4)#? Algebra Polynomials and Factoring Multiplication of Polynomials by Binomials 1 Answer Tessalsifi Jun 5, 2015 How to foil : #(a+b)(c+d)=ac+ad+bc+bd# Thus : #(3y-2)(2y-4)=3y*2y+3y*(-4)+(-2)*2y+(-2)(-4)# #=6y²-12y-4y+8=6y²-16y+8# You can factorize by #2# : #=2*(3y²-8y+4)# Answer link Related questions What is FOIL? How do you use the distributive property when you multiply polynomials? How do you multiply #(x-2)(x+3)#? How do you simplify #(-4xy)(2x^4 yz^3 -y^4 z^9)#? How do you multiply #(3m+1)(m-4)(m+5)#? How do you find the volume of a prism if the width is x, height is #2x-1# and the length if #3x+4#? How do you multiply #(a^2+2)(3a^2-4)#? How do you simplify #(x – 8)(x + 5)#? How do you simplify #(p-1)^2#? How do you simplify #(3x+2y)^2#? See all questions in Multiplication of Polynomials by Binomials Impact of this question 1624 views around the world You can reuse this answer Creative Commons License