How is the peak affected in C^13 NMR by the number of H's attached to the carbon?

1 Answer
Jun 6, 2015

In a "normal" ""^13"C" NMR spectrum, the number of "H" atoms attached to the carbon does not affect the peak.

That's because most ""^13"C" NMR spectra are broadband decoupled .

The couplings are removed by applying a continuous second radio signal that excites all the protons and cancels out their couplings with the "C" atoms.

Thus, the spectrum of 2-bromobutane consists of four singlets.

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However, there is a technique called off-resonance decoupling , in which only the protons bonded to a given carbon atom split its signal.

Thus, a "CH"_3 group appears as a quartet, a "CH"_2 group appears as a triplet, a "CH" group appears as a doublet, and a quaternary "C" appears as a singlet.

So, the off-resonance decoupled spectrum of 2-bromobutane consists of two quartets, a triplet, and a doublet.

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