How do you multiply # (2x^4)/ (10y^2) * ( 5y^3)/(4x^3)#?

Question

2323 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-06-08T00:00:06

#(2x^4)/(10y^2)*(5y^3)/(4x^3)#

I simplify "in cross" the two cohefficients:

#(2x^4)/(2y^2)*(y^3)/(4x^3) # (simplified 10 and 5)

#(x^4)/(y^2)*(y^3)/(2x^3)# (simplified 4 and 2)

Now I multiply the variables together and I order them to work properly:

#(x^4y^3)/(2x^3y^2)#

Assuming that #x!=0# and #y!=0#, I can reduce the degree of the variables in this way:

#(x^(4-3)*y^(3-2))/(2*x^(3-3)*y^(2-2))#

That is basically:

#(xy)/2#