How do you use factoring to solve this equation #3x^2/4=27#?

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Answer 1 · 2015-06-08T18:09:59

#27=3*9#

Thus :

#cancel3(x²)/4=cancel3*9#

#(x²)/4=9#

#x²=9*4# ( we multiply by 4 on each side )

#x²=36#

Thus :

#x=sqrt36#
=> #x=6#

Or :
#x=-sqrt36#
=> #x=-6#