Question

Given: `f(x) = 2+ sqrt(-3x+1)`, `q(x) = (5x)/(x+2)`, and `m(x) = abs(7 - x^2) + x`, how do you find f(-33)?

Answer 1

You can simply substitute x with -33 in f(x) function:
`f(-33)=12`.

Explanation:

`f(x)=2+sqrt(−3x+1)`

`q(x)=(5x)/(x+2)`
`m(x)=∣7−x^2∣+x`

How do you find f(-33)?
`f(-33)=2+sqrt(-3*-33+1)=2+sqrt(100)=2+10=12`