Question #8acfd

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Question #8acfd

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Answer 1 · 2015-06-18T08:52:03

The value of $n$ $n$ is $\frac{\sqrt[5]{10}}{5}$ $root(5)(10)/5$

Explanation:

When you substitute values for x,a and b you get:
$2 = 10 {log}_{10} (\frac{25 n}{5})$ $2=10log_10 ((25n)/5)$
$2 = 10 {log}_{10} 5 n$ $2=10log_10 5n$
$\frac{1}{5} = {log}_{10} 5 n$ $1/5=log_10 5n$
${log}_{10} (10^{\frac{1}{5}}) = {log}_{10} 5 n$ $log_10 (10^(1/5))=log_10 5n$
$10^{\frac{1}{5}} = 5 n$ $10^(1/5)=5n$
$n = \frac{10^{\frac{1}{5}}}{5}$ $n=10^(1/5)/5$

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Question #8acfd

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