Question

How do you solve `sin 3 theta = 1`?

Answer 1

`theta=pi/6+2/3npi` where `n` is an integer.

Explanation:

Knowing that `sin(pi/2)=1`

Knowing that `sin(x+2pi)=sin(x)`

then `3theta=pi/2+2npi` where `n` is an integer

`rarr theta=(pi/2+2npi)/3=pi/6+2/3npi`