Question

How do you evaluate `arcsin(cos(pi/3))`?

Answer 1

Answer is `pi/6`

Explanation:

`sin^(-1)(cos(pi/3))=sin^-1(1/2)` (since `cos60^@=1/2)`

`sin^(-1)(cos(pi/3))=sin^-1(sin(pi/6))`[since from angle table]

`sin^(-1)(cos(pi/3))=cancelsin^-1(cancel(sin)(pi/6))`

`arcsin(cos(pi/3))=pi/6`