How do you solve $3 x + 4 = - 8$ $3x + 4 =-8$ ?

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Answer 1 · 2015-06-28T19:08:51

The answer will be
$x = 4$ $x = 4$

Explanation:
First, we will take the $+ 4$ $+4$ to the RHS. As it is positive, sending to RHS will make it negative.Therefore

$3 x = - 8 - 4$ $3x= -8-4$
$3 x = - 12$ $3x=-12$

Now we will send 3 to the RHS. As 3 is in multiply, sending it to RHS will make it a divisor.

$x = - \frac{12}{3}$ $x=-12/3$

Hence

$x = 4$ $x=4$

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