Question

How do you solve 4 > -3x + 3 or 8 ≤ -2x + 5?

Answer 1

`4> -3x+3 rarr x> -1/3`

`8<=-2x+5 rarr x<=-3/2`

Explanation:

Solving an inequation is the same as solving an equation, except that the orientation of the inequality will change when you multiply or divide by a negative number.

Let's start with `4> -3x+3`

`rarr 4-3> -3x+cancel(3)-cancel(3)`
`rarr 1/3 > -(cancel(3)x)/cancel(3)`
`rarr -1/3 < -(-x) rarr x> -1/3`

Now `8<=-2x+5`

`rarr 8-5<=-2x+cancel(5)-cancel(5)`
`rarr 3/2<=-(cancel(2)x)/cancel(2)`
`rarr -3/2>=-(-x) rarr x <= -3/2`