How do you translate to an algebraic expression 6 less than x cubed?

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How do you translate to an algebraic expression 6 less than x cubed?

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Answer 1 · 2015-07-02T18:08:25

$x^{3} - 6$ $x^3-6$

Explanation:

For problems like this, it's good to be break up the information and visualize how it fits in together.

So we're told we have a $6$ $6$ . We're also told we have an $x^{3}$ $x^3$ (x cubed).

The question tells us that there is $6$ $6$ less than $x^{3}$ $x^3$ . That means that $6$ $6$ is always being taken away from $x^{3}$ $x^3$ , being subtracted from it.

Therefore, the expression would be:
$x^{3} - 6$ $x^3-6$
which you could make into a function:
$f (x) = x^{3} - 6$ $f(x)=x^3-6$

Answer 2 · 2015-07-03T17:27:34

$6$ $6$ < $x^{3}$ $x^3$

Explanation:

This is an alternative way to interpret the question; as an inequality

We are told that we have $6$ $6$ less than $x^{3}$ $x^3$

$6$ $6$ less than $x^{3}$ $x^3$ = $6$ $6$ < $x^{3}$ $x^3$ since "<" is the "less than" sign

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How do you translate to an algebraic expression 6 less than x cubed?

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