How do you find the exact value of $sin ({sin}^{- 1} (\frac{1}{3}))$ $sin(sin^-1 (1/3))$ ?

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Answer 1 · 2015-07-12T10:26:23

The answer will be $\frac{1}{3}$ $1/3$

As we know,

$sin ({sin}^{- 1} x) = x$ $Sin(Sin ^ -1 x) = x$

Therefore,

$sin [{sin}^{- 1} (\frac{1}{3})] = \frac{1}{3}$ $Sin[Sin^-1 (1/3)] = 1/3$

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