How do you solve the simultaneous equations $2 x + 3 y = 6$ $2x+3y=6$ and $3 x - 2 y = 22$ $3x-2y=22$ ?

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Answer 1 · 2015-07-23T06:50:52

${ (x=6), (y = -2) :}$

Simply multiply the first equation thoroughly by $2$ and the second equation by $3$ and subtract the results...

After the described multiplication, we get the result as

$4x + 6y = 12$
$9x - 6y = 66$
$stackrel("---------------------------")$

$13x = 78 implies x = 78/13 = 6$

Putting the value of $y$ into the first equation, we have

$2 * 6 + 3y = 6$

$3y = 6 - 12$

$3y = -6 implies x = ((-6))/3 = -2$

How do you solve the simultaneous equations 2x+3y=6 2x+3y=62x+3y=6 and 3x-2y=223x−2y=223x-2y=22?