How do you solve the simultaneous equations #2x+3y=6 # and #3x-2y=22#?
1 Answer
Explanation:
Simply multiply the first equation thoroughly by
After the described multiplication, we get the result as
#4x + 6y = 12#
#9x - 6y = 66#
#stackrel("---------------------------")#
#13x = 78 implies x = 78/13 = 6#
Putting the value of
#2 * 6 + 3y = 6#
#3y = 6 - 12#
#3y = -6 implies x = ((-6))/3 = -2#