How do you solve # 5b + 2 = 17#?

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Answer 1 · 2015-07-27T07:38:30

#b= 3#

We will group the numbers with each other and leave the the variable #b# alone on one side of the equation.

This means that you will have #+2# to be next to the 17, but because the 17 is on the other side of the equation, #+2# will become #-2#.

#5b = 17 - 2#

#5b = 15#

Therefore,

#b = 15/5#

now divide both sides of the equation by #5# to get

#(cancel(5) * b)/cancel(5) = 15/5#

#b = 3#