How do you solve #18 - 4n = 62#?

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Answer 1 · 2015-07-27T10:31:28

#n=-11#

This can be solve by using simple algebraic properties. Here we have;

#18-4n=62#

Subtract 18 on both side, we get;

#=>18-4n-18=62-18#
#=>-4n=44#

Divide each side by -4, we get;

#=>{-4n}/{-4}=44/{-4}#

Cancel out the common factors, we get;

#=>n=-11#

Thanks