How do you find the period of y= -4 cos 2xy=4cos2x?

1 Answer
Jul 28, 2015

piπ

Explanation:

Let us look at a more general problem: f(x) = A cos(nx)f(x)=Acos(nx). In this case, we have f(x + 2pi/n) = A cos(n(x + 2pi/n)) = A cos(nx + 2pi) = A cos(nx) f(x+2πn)=Acos(n(x+2πn))=Acos(nx+2π)=Acos(nx). Try this also for sinsin; it is exactly the same.

Thus we see that the period of such a general function is (2pi)/n 2πn.

Therefore for f(x) = -4 cos(2x)f(x)=4cos(2x), the period is (2pi)/n = (cancel2 pi)/cancel2 = pi .