How do you solve $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?

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How do you solve $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?

2 Answers

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Answer 1 · 2015-08-04T18:14:38

There is no unique solution for the given equation(s)

Explanation:

[1] $XXXX$ $color(white)("XXXX")$ $x - 4 y = - 8$ $x-4y=-8$
and
[2] $XXXX$ $color(white)("XXXX")$ $- 3 x + 12 y = 24$ $-3x+12y=24$

are actually the same equation
$XXXX$ $color(white)("XXXX")$ $XXXX$ $color(white)("XXXX")$ ([1} multiplied by $(- 3)$ $(-3)$ is the same as [2])

They are not 2 intersecting equations.

Answer 2 · 2015-08-04T18:15:27

You have $\infty$ $oo$ solutions.

Explanation:

The second equation is equal to the first one multiplied by $- 3$ $-3$ ; so basically you have two equations representing two coincident lines (technically one on top of the other) so your system has $\infty$ $oo$ solutions corresponding to the $\infty$ $oo$ number of common points between the two lines!

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How do you solve $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?

2 Answers

Explanation:

Explanation:

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Science

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Humanities

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How do you solve x−4y=−8x-4y=-8 and −3x+12y=24-3x+12y=24?

2 Answers

Explanation:

Explanation:

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Impact of this question

How do you solve $x - 4 y = - 8$ $x-4y=-8$ and $- 3 x + 12 y = 24$ $-3x+12y=24$ ?