How do you solve the simultaneous equations $6 x + 2 y = 50$ $6x + 2y = 50$ and $2 x + 4 y = 20$ $2x + 4y = 20$ ?

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Answer 1 · 2015-08-09T07:29:58

${(x = 8), (y = 1) :}$

$6x + 2y = 50" " " " " "(1)$

Can be written as

$6x + 2y - 50 = 0$

$2x + 4y = 20 " " " " " (2)$

Can be written as

$2x + 4y - 20 = 0$

To eliminate $x$ , let us multiply equation $(2)$ by $3$ ; then it becomes -

$6x + 12y - 60 = 0$

Since both equations are equal to zero; we shall have them like this-

$6x + 2y - 50 = 6x + 12y - 60$

Take the unknowns to left and the constants to the right.

$cancel(6x) + 2y - cancel(6x) - 12y = - 60 + 50$

$- 10y = - 10 implies y = ((-10))/((-10)) = 1$

Substitute $y = 1$ in equation $(1)$

$6x + 2 * 1 = 50$

$6x = 50 -2$

$x = 48/6 = 8$

How do you solve the simultaneous equations 6x + 2y = 506x+2y=506x + 2y = 50 and 2x + 4y = 202x+4y=202x + 4y = 20?