How do you solve $5 r^{2} - 44 r + 120 = - 30 + 11 r$ $5r^2 - 44r + 120 = -30 + 11r$ by factoring?

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How do you solve $5 r^{2} - 44 r + 120 = - 30 + 11 r$ $5r^2 - 44r + 120 = -30 + 11r$ by factoring?

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Answer 1 · 2015-08-09T17:30:44

$r = 5, 6$ $r = 5, 6$

Explanation:

$5 r^{2} - 44 r + 120 = - 30 + 11 r$ $5 r^2 - 44 r + 120 = -30 + 11 r$
$\Rightarrow 5 r^{2} - 55 r + 150 = 0$ $=> 5 r^2 - 55 r + 150 = 0$ (Adding $30 - 11 r$ $30 - 11 r$ to both sides)
$\Rightarrow r^{2} - 11 r + 30 = 0$ $=> r^2 - 11 r + 30 = 0$ (Dividing by 5)
$\Rightarrow r^{2} - 5 r - 6 r + 30 = 0$ $=> r^2 - 5 r - 6 r + 30 = 0$ (Noting that $30 = 5 \cdot 6$ $30 = 5 * 6$ , and that $5 + 6 = 11$ $5 + 6 = 11$ )
$\Rightarrow r (r - 5) - 6 (r - 5) = 0$ $=> r ( r - 5 ) - 6 ( r - 5 ) = 0$
$\Rightarrow (r - 5) (r - 6) = 0$ $=> ( r - 5 ) ( r - 6 ) = 0$
$\Rightarrow r = 5$ $=> r = 5$ or $r = 6$ $r = 6$

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How do you solve $5 r^{2} - 44 r + 120 = - 30 + 11 r$ $5r^2 - 44r + 120 = -30 + 11r$ by factoring?

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Explanation:

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How do you solve 5r2−44r+120=−30+11r5r^2 - 44r + 120 = -30 + 11r by factoring?

1 Answer

Explanation:

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How do you solve $5 r^{2} - 44 r + 120 = - 30 + 11 r$ $5r^2 - 44r + 120 = -30 + 11r$ by factoring?