How do you write $y + \frac{1}{3} x = 4$ $y + 1/3x = 4$ into slope intercept form?

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How do you write $y + \frac{1}{3} x = 4$ $y + 1/3x = 4$ into slope intercept form?

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Answer 1 · 2015-08-11T00:22:09

$y = - \frac{1}{3} x + 4$ $y=-1/3x+4$

Explanation:

Slope intercept form can be represented as $y = m x + b$ $y=mx +b$
To get an equation into this form, we should try to get $y$ $y$ all alone.

From $y + \frac{1}{3} x = 4$ $y+1/3x=4$
we can subtract $\frac{1}{3} x$ $1/3x$ from both sides
to get $\Rightarrow y = - \frac{1}{3} x + 4$ $=>y= -1/3x+4$
which is now in slope intercept form :)

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How do you write $y + \frac{1}{3} x = 4$ $y + 1/3x = 4$ into slope intercept form?

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How do you write $y + \frac{1}{3} x = 4$ $y + 1/3x = 4$ into slope intercept form?