#cos 2x csc x - 2 cos 2x = 0# #cos 2x (csc x - 2) = 0#
Solution A: #cos 2x = 0 \Rightarrow 2x = pmpi/2 + kpi \Rightarrow x = pi/4 (2kpm1), k in ZZ#
Solution B: #1/cos x = 2 \Rightarrow cos x = 1/2 \Rightarrow x = pmpi/3 + 2kpi = pi/3 (6k+-1), k in ZZ# #therefore x = pi/4 (2kpm1)# or #x = pi/3 (6k+-1), k in ZZ#