How do you solve abs(2x + 3) - 6 = 11 ? Algebra Linear Inequalities and Absolute Value Absolute Value Equations 1 Answer dani83 Aug 17, 2015 x = 7 or x = -10 Explanation: |2x+3| = 17 Method 1: 2x+3 = 17, " if " 2x+3 > 0 x = 7 -(2x+3) = 17, " if " 2x+3 < 0 x = -10 Method 2: (2x+3)^2 = 17^2 x^2 + 3x - 70 = 0 (x-7)(x+10) = 0 x = 7 or x = -10 Answer link Related questions How can an absolute value equation have no solution? How can an absolute value equation have one solution? How do you solve absolute value equations? How do you solve |x - 5| = 10? How do you solve 8=3+|10y+5|? How do you solve 8|x+6|=-48? Can an absolute value equation ever have and infinite amount of solutions? What do you do when you have absolute values on both sides of the equations? How do you solve for m given |\frac{m}{8}|=1? How do you solve 3abs(-9 x-7)-2=13? See all questions in Absolute Value Equations Impact of this question 1491 views around the world You can reuse this answer Creative Commons License