How do you solve $| 2 x + 3 | - 6 = 11$ $abs(2x + 3) - 6 = 11$ ?

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How do you solve $| 2 x + 3 | - 6 = 11$ $abs(2x + 3) - 6 = 11$ ?

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Answer 1 · 2015-08-17T13:57:11

$x = 7$ $x = 7$ or $x = - 10$ $x = -10$

Explanation:

$| 2 x + 3 | = 17$ $|2x+3| = 17$

Method 1:
$2 x + 3 = 17, if 2 x + 3 > 0$ $2x+3 = 17, " if " 2x+3 > 0$
$x = 7$ $x = 7$

$- (2 x + 3) = 17, if 2 x + 3 < 0$ $-(2x+3) = 17, " if " 2x+3 < 0$
$x = - 10$ $x = -10$

Method 2:
${(2 x + 3)}^{2} = 17^{2}$ $(2x+3)^2 = 17^2$
$x^{2} + 3 x - 70 = 0$ $x^2 + 3x - 70 = 0$
$(x - 7) (x + 10) = 0$ $(x-7)(x+10) = 0$
$x = 7$ $x = 7$ or $x = - 10$ $x = -10$

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How do you solve $| 2 x + 3 | - 6 = 11$ $abs(2x + 3) - 6 = 11$ ?

1 Answer

Explanation:

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Science

Math

Humanities

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How do you solve |2x+3|−6=11abs(2x + 3) - 6 = 11 ?

1 Answer

Explanation:

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Impact of this question

How do you solve $| 2 x + 3 | - 6 = 11$ $abs(2x + 3) - 6 = 11$ ?