How do you graph and find the discontinuities of 1 /(x+6)?

1 Answer
Aug 29, 2015

graph{1/(x+6) [-10, 10, -5, 5]} and x=-6

Explanation:

Essentially it's transforming the graph y=1/x into y=1/(x+6) by translating x 6 units in the negative x-direction. Discontinuities occur when the function is undefined, i.e. x=-6, at which the graph is undefined. You can show this by drawing the vertical like x=6 and showing that this line never intersects the graph of y=1/(x+6)