How do you graph $y = 3 {(x + 3)}^{2} - 3$ $y=3(x+3)^2 - 3$ ?

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How do you graph $y = 3 {(x + 3)}^{2} - 3$ $y=3(x+3)^2 - 3$ ?

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Answer 1 · 2015-09-09T18:21:57

If you expand it you get $y = 3 x^{2} + 18 x + 24$ $y=3x^2+18x+24$

Explanation:

With graph

graph{3x^2+18x+24 [-10, 10, -5, 5]}

Answer 2 · 2015-09-09T19:51:30

See the explanation section.

Explanation:

For $y = a {(x - h)}^{2} + k$ $y = a(x-h)^2 +k$ the vertex is $(h, k)$ $(h,k)$ and the graph opens from the vertex through the points $x = h \pm 1$ $x = h +-1$ and $y = k + a$ $y = k +a$ That is, through the points $(h + 1, k + a)$ $(h+1, k+a)$ and $(h - 1, k + a)$ $(h-1, k+a)$

For $y = 3 {(x + 3)}^{2} - 3$ $y = 3(x+3)^2-3$ , the vertex is $(- 3, - 3)$ $(-3,-3)$ and with $a = 3$ $a=3$ , the parabola opens upward through the points $x = - 3 \pm 1$ $x= -3 +-1$ and $y = - 3 + 3 = 0$ $y = -3+3 = 0$ . That is, through the points $(- 2, 0)$ $(-2,0)$ and $(- 4, 0)$ $(-4,0)$

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How do you graph $y = 3 {(x + 3)}^{2} - 3$ $y=3(x+3)^2 - 3$ ?

2 Answers

Explanation:

Explanation:

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How do you graph y=3(x+3)2−3y=3(x+3)^2 - 3?

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How do you graph $y = 3 {(x + 3)}^{2} - 3$ $y=3(x+3)^2 - 3$ ?