Question

How do you graph and find the discontinuities of `(x^2)/(x-1)`?

Answer 1

The function is discontinuous at `x=1`

Explanation:

We notice that as `x->1` we have that `x^2/(x-1)->oo`. So at `x=1` there is a discontinuity.

The graph is as follows

graph{x^2/(x-1) [-20, 20, -10, 10]}