How do I find the value of cos pi/12?

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How do I find the value of cos pi/12?

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Answer 1 · 2015-09-11T17:30:26

It is $cos (\frac{π}{12}) = \frac{1}{4} \cdot (\sqrt{2} + \sqrt{6})$ $cos(pi/12)=1/4*(sqrt2+sqrt6)$

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$cos (\frac{π}{12}) = cos (\frac{π}{3} - \frac{π}{4}) = cos (\frac{π}{4}) cos (\frac{π}{3}) + sin (\frac{π}{4}) sin (\frac{π}{3}) = \frac{\sqrt{2}}{2} \cdot \frac{1}{2} + \frac{\sqrt{2}}{2} \cdot \frac{\sqrt{3}}{2} = \frac{1}{4} \cdot (\sqrt{2} + \sqrt{2} \cdot \sqrt{3}) = \frac{1}{4} (\sqrt{2} + \sqrt{6})$ $cos(pi/12)=cos(pi/3-pi/4)=cos(pi/4)cos(pi/3)+sin(pi/4)sin(pi/3)=sqrt2/2*1/2+sqrt2/2*sqrt3/2=1/4*(sqrt2+sqrt2*sqrt3)=1/4(sqrt2+sqrt6)$

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How do I find the value of cos pi/12?

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