How do you divide $2 x^{2} + 9 x + 4 \div 2 x + 1$ $2x^2+9x+4 div 2x+1$ ?

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Answer 1 · 2015-09-13T16:11:50

refer the explanation

easy method

$\frac{2 x^{2} + 9 x + 4}{2 x - 1}$ $(2x^2 + 9x + 4)/(2x-1)$

you can easily divide the numerator into its factors.

$\frac{(2 x + 1) (x + 4)}{2 x + 1}$ $[(2x+1)(x+4)]/(2x+1)$

cut off the $(2 x + 1)$ $(2x+1)$

the answer is (x+4)

long method

if u want to make it the long way, u can use long division to divide this polynomial as well

How do you divide 2x^2+9x+4 div 2x+1 2x2+9x+4÷2x+12x^2+9x+4 div 2x+1 ?