Question #4013a

Question

Question #4013a

2 Answers

Impact of this question

9543 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-09-15T18:11:55

$3, 0115 \times 10^{26}$ $3,0115xx10^(26)$

Explanation:

Number of moles of hydrogen present is $n = \frac{m}{M r} = \frac{1000 g}{2 g / m o l} = 500 m o l$ $n=m/(Mr)=(1000g)/(2g//mol)=500 mol$
Note that the molar mass of hydrogen is 2g/mol since it is diatomic in nature.
Hence, to find number of molecules present, we must multiply the number of moles by the Avogadro constant which is the number of particles per mole.
ie $n \times N_{A} = 500 \times 6, 023 \times 10^{23} = 3, 0115 \times 10^{26}$ $nxxN_A = 500xx6,023xx10^(23)=3,0115xx10^(26)$

Answer 2 · 2015-09-15T18:18:32

$3.011 \times 10^{26}$ $3.011 xx 10^(26)$ molecules

Explanation:

To figure out the number of molecules of hydrogen in 1.0 kg of hydrogen gas we need first to find the number of mole ( $n$ $n$ ), then:

$no. of molecules = no. of moles \times Avogadro's number$ $"no. of molecules" = "no. of moles" xx "Avogadro's number"$

the number of mole n = $\frac{m}{MM}$ $(m)/"MM"$ , where MM is the molar mass which is equal to 2.0 g/mol. And m = 1 kg = 1000 g.

Therefore,

$n = \frac{1000}{2.0} = 500 mol = 5.0 \times 10^{2} mol$ $n = (1000)/"2.0" = "500 mol" = 5.0 xx 10^2 "mol"$

Therefore,

$"no. of molecules" = 5.0 xx 10^2 cancel("mol") xx 6.022 xx 10^(23)"molecules"/cancel("mol")$

$"no. of molecules" = 3.011 xx 10^(26) "molecules"$

Science

Math

Humanities

... and beyond

Question #4013a

2 Answers

Explanation:

Explanation:

Related questions

Impact of this question