How do you find the integral of #((x)sqrt(x-1))dx#?
1 Answer
Sep 19, 2015
Explanation:
Let x-1 = u
this gives x = u+1
that is dx = du
after substitution integral changes to
Integral ((u+1)
=
=
=
=
Answer: (2/5)(x-1)^(5/2) + (2/3)(x-1)^(3/2) + C