Question

How do you simplify `sqrt(2x ) div sqrt(9x)`?

Answer 1

`sqrt2/3`

Explanation:

Rewrite in fractional form:
`sqrt(2x) -: sqrt(9x) = sqrt(2x)/sqrt(9x)`

Remember the rule:
`sqrt(ab)=sqrt(a)sqrt(b)`

so breaking down the roots, we get:
`= (sqrt(2)sqrt(x))/(sqrt(9)sqrt(x))`

Now, `sqrt(x)/sqrt(x)=1` so that's gone, and `sqrt(9)=3`, so we end up having:
`= sqrt2/3`