How do I find the value of tan 5pi / 6? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer Dharma R. · Stefan V. Sep 21, 2015 #-sqrt(3)/3# Explanation: #tan((5pi)/6)=tan(pi-pi/6)=(tanpi-tan(pi/6))/(1+tan(pi)tan(pi/6))=-tan(pi/6)=-1/sqrt3 = -sqrt(3)/3# Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 89237 views around the world You can reuse this answer Creative Commons License
