Question #7a4fb

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Question #7a4fb

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Answer 1 · 2015-09-23T15:43:55

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Explanation:

The marginal rate of technical substitution can be defined as

$M R = - \frac{\frac{d f}{{d x}_{1}}}{\frac{d f}{{d x}_{2}}} = - \frac{\frac{3}{4} \cdot {(x_{1})}_{1}^{- \frac{1}{4}} \cdot {(x_{2})}_{2}^{\frac{1}{4}}}{{(x_{1})}_{1}^{\frac{3}{4}} \cdot (\frac{1}{4}) \cdot {(x_{2})}_{2}^{- \frac{3}{4}}} = - 3 \cdot \frac{x_{2}}{x_{1}}$ $MR=-((df)/dx_1)/((df)/dx_2)=-(3/4*(x_1)^(-1/4)*(x_2)^(1/4))/((x_1)^(3/4)*(1/4)*(x_2)^(-3/4))=-3*(x_2)/(x_1)$

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