Question

How do you find the inverse of `f(x)=(3x-2)/(x+7)`?

Answer 1

`f^(-1)x=(7x+2)/(3-x)`

Explanation:

`y=f(x)=(3x-2)/(x+7)=(3x+21-23)/(x+7)=3-23/(x+7)`
`y=3-23/(x+7)=>(y-3)=-23/(x+7)=>x+7=23/(3-y)=>x=-7+23/(3-y)`
`f^(-1)y=-7+23/(3-y)=(7y+2)/(3-y)`
`=>f^(-1)x=(7x+2)/(3-x)`