How do you solve #-x^2-4x>3#? Precalculus Solving Rational Inequalities Polynomial Inequalities 1 Answer iceman Sep 27, 2015 #-3 < x <-1# Explanation: #-x^2-4x>3=># multiply by -1, reverse direction of inequality: #x^2+4x<-3=># solving by completing the square: #x^2+4x+4<4-3# #(x+2)^2<1# #-1 < (x+2)<1# #-3 < x <-1# In interval form: #(-3, -1)# Answer link Related questions What are common mistakes students make when solving polynomial inequalities? How do I solve a polynomial inequality? How do I solve the polynomial inequality #-2(m-3)<5(m+1)-12#? How do I solve the polynomial inequality #-6<=2(x-5)<7#? How do I solve the polynomial inequality #1<2x+3<11#? How do I solve the polynomial inequality #-12<-2(x+1)<=18#? How do you solve the inequality #6x^2-5x>6#? How do you solve #x^2 - 4x - 21<=0# A) [-3, 7] B) (-∞, -3] C) (-∞, -3] [7, ∞) D) [7, ∞)? How do you solve quadratic inequality, graph, and write in interval notation #x^2 - 8x + 15 >0#? How do you solve #-x^2 - x + 6 < 0#? See all questions in Polynomial Inequalities Impact of this question 1814 views around the world You can reuse this answer Creative Commons License