How do you find the vertex and axis of symmetry, and then graph the parabola given by: $h (x) = - 2 {(x - 1)}^{2} - 3$ $h(x)=-2(x-1)^2-3$ ?

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Answer 1 · 2015-09-28T07:52:35

vertex $(1, - 3)$ $(1, -3)$

Its axis of symmetry is -

$x = 1$ $x=1$

It passes through the vertex.

Symmetry

x: y
4: -21
3: -11
2: -5
1: -3
0: -5
-1: -11
-2: -21

graph{-2(x-1)^2-3 [-22.81, 22.8, -11.4, 11.42]} -21

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How do you find the vertex and axis of symmetry, and then graph the parabola given by: h(x)=−2(x−1)2−3 h(x)=-2(x-1)^2-3?