How do you simplify $125^{- \frac{2}{3}}$ $125^ (-2/3)$ ?

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How do you simplify $125^{- \frac{2}{3}}$ $125^ (-2/3)$ ?

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Answer 1 · 2015-09-30T06:11:29

$.04$ $.04$

Explanation:

$x^{- y} = \frac{1}{x^{y}}$ $x^-y= 1/x^y$
$125^{- \frac{2}{3}} = \frac{1}{{(125^{\frac{1}{3}})}^{2}}$ $125^(-2/3)= 1/((125^(1/3))^2$ $= \frac{1}{5^{2}} = \frac{1}{25} = .04$ $= 1/5^2= 1/25 = .04$

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How do you simplify $125^{- \frac{2}{3}}$ $125^ (-2/3)$ ?

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