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How do you factor $4 x^{2} - 4 x = 0$ $4x^2-4x=0$ ?

1 Answer

Vishwaksen Reddy V.

Oct 1, 2015

$x = 0$ $x=0$ or $x = 1$ $x=1$

Explanation:

$4 \cdot x^{2} + 4 \cdot x = 0$ $4*x^2+4*x=0$
$4 \cdot x \cdot (x - 1) = 0$ $4*x*(x-1)=0$
so
$x = 0$ $x=0$ or $x = 1$ $x=1$

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